Optimal. Leaf size=88 \[ -\frac{\left (a^2 B-2 a b C-b^2 B\right ) \log (\sin (c+d x))}{d}-\frac{a^2 B \cot ^2(c+d x)}{2 d}+x \left (b^2 C-a (a C+2 b B)\right )-\frac{a (a C+2 b B) \cot (c+d x)}{d} \]
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Rubi [A] time = 0.263472, antiderivative size = 88, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.125, Rules used = {3632, 3604, 3628, 3531, 3475} \[ -\frac{\left (a^2 B-2 a b C-b^2 B\right ) \log (\sin (c+d x))}{d}-\frac{a^2 B \cot ^2(c+d x)}{2 d}+x \left (b^2 C-a (a C+2 b B)\right )-\frac{a (a C+2 b B) \cot (c+d x)}{d} \]
Antiderivative was successfully verified.
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Rule 3632
Rule 3604
Rule 3628
Rule 3531
Rule 3475
Rubi steps
\begin{align*} \int \cot ^4(c+d x) (a+b \tan (c+d x))^2 \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx &=\int \cot ^3(c+d x) (a+b \tan (c+d x))^2 (B+C \tan (c+d x)) \, dx\\ &=-\frac{a^2 B \cot ^2(c+d x)}{2 d}+\int \cot ^2(c+d x) \left (a (2 b B+a C)-\left (a^2 B-b^2 B-2 a b C\right ) \tan (c+d x)+b^2 C \tan ^2(c+d x)\right ) \, dx\\ &=-\frac{a (2 b B+a C) \cot (c+d x)}{d}-\frac{a^2 B \cot ^2(c+d x)}{2 d}+\int \cot (c+d x) \left (-a^2 B+b^2 B+2 a b C+\left (b^2 C-a (2 b B+a C)\right ) \tan (c+d x)\right ) \, dx\\ &=\left (b^2 C-a (2 b B+a C)\right ) x-\frac{a (2 b B+a C) \cot (c+d x)}{d}-\frac{a^2 B \cot ^2(c+d x)}{2 d}+\left (-a^2 B+b^2 B+2 a b C\right ) \int \cot (c+d x) \, dx\\ &=\left (b^2 C-a (2 b B+a C)\right ) x-\frac{a (2 b B+a C) \cot (c+d x)}{d}-\frac{a^2 B \cot ^2(c+d x)}{2 d}-\frac{\left (a^2 B-b^2 B-2 a b C\right ) \log (\sin (c+d x))}{d}\\ \end{align*}
Mathematica [C] time = 0.342002, size = 123, normalized size = 1.4 \[ \frac{-2 \left (a^2 B-2 a b C-b^2 B\right ) \log (\tan (c+d x))-a^2 B \cot ^2(c+d x)-2 a (a C+2 b B) \cot (c+d x)+(a-i b)^2 (B-i C) \log (\tan (c+d x)+i)+(a+i b)^2 (B+i C) \log (-\tan (c+d x)+i)}{2 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.095, size = 141, normalized size = 1.6 \begin{align*}{\frac{{b}^{2}B\ln \left ( \sin \left ( dx+c \right ) \right ) }{d}}+{b}^{2}Cx+{\frac{C{b}^{2}c}{d}}-2\,Babx-2\,{\frac{B\cot \left ( dx+c \right ) ab}{d}}-2\,{\frac{Babc}{d}}+2\,{\frac{Cab\ln \left ( \sin \left ( dx+c \right ) \right ) }{d}}-{\frac{{a}^{2}B \left ( \cot \left ( dx+c \right ) \right ) ^{2}}{2\,d}}-{\frac{{a}^{2}B\ln \left ( \sin \left ( dx+c \right ) \right ) }{d}}-Cx{a}^{2}-{\frac{C\cot \left ( dx+c \right ){a}^{2}}{d}}-{\frac{C{a}^{2}c}{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.69442, size = 162, normalized size = 1.84 \begin{align*} -\frac{2 \,{\left (C a^{2} + 2 \, B a b - C b^{2}\right )}{\left (d x + c\right )} -{\left (B a^{2} - 2 \, C a b - B b^{2}\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right ) + 2 \,{\left (B a^{2} - 2 \, C a b - B b^{2}\right )} \log \left (\tan \left (d x + c\right )\right ) + \frac{B a^{2} + 2 \,{\left (C a^{2} + 2 \, B a b\right )} \tan \left (d x + c\right )}{\tan \left (d x + c\right )^{2}}}{2 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.4326, size = 285, normalized size = 3.24 \begin{align*} -\frac{{\left (B a^{2} - 2 \, C a b - B b^{2}\right )} \log \left (\frac{\tan \left (d x + c\right )^{2}}{\tan \left (d x + c\right )^{2} + 1}\right ) \tan \left (d x + c\right )^{2} + B a^{2} +{\left (B a^{2} + 2 \,{\left (C a^{2} + 2 \, B a b - C b^{2}\right )} d x\right )} \tan \left (d x + c\right )^{2} + 2 \,{\left (C a^{2} + 2 \, B a b\right )} \tan \left (d x + c\right )}{2 \, d \tan \left (d x + c\right )^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 30.6038, size = 206, normalized size = 2.34 \begin{align*} \begin{cases} \text{NaN} & \text{for}\: c = 0 \wedge d = 0 \\x \left (a + b \tan{\left (c \right )}\right )^{2} \left (B \tan{\left (c \right )} + C \tan ^{2}{\left (c \right )}\right ) \cot ^{4}{\left (c \right )} & \text{for}\: d = 0 \\\text{NaN} & \text{for}\: c = - d x \\\frac{B a^{2} \log{\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 d} - \frac{B a^{2} \log{\left (\tan{\left (c + d x \right )} \right )}}{d} - \frac{B a^{2}}{2 d \tan ^{2}{\left (c + d x \right )}} - 2 B a b x - \frac{2 B a b}{d \tan{\left (c + d x \right )}} - \frac{B b^{2} \log{\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 d} + \frac{B b^{2} \log{\left (\tan{\left (c + d x \right )} \right )}}{d} - C a^{2} x - \frac{C a^{2}}{d \tan{\left (c + d x \right )}} - \frac{C a b \log{\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{d} + \frac{2 C a b \log{\left (\tan{\left (c + d x \right )} \right )}}{d} + C b^{2} x & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 2.04962, size = 320, normalized size = 3.64 \begin{align*} -\frac{B a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 4 \, C a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 8 \, B a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 8 \,{\left (C a^{2} + 2 \, B a b - C b^{2}\right )}{\left (d x + c\right )} - 8 \,{\left (B a^{2} - 2 \, C a b - B b^{2}\right )} \log \left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right ) + 8 \,{\left (B a^{2} - 2 \, C a b - B b^{2}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) \right |}\right ) - \frac{12 \, B a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 24 \, C a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 12 \, B b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 4 \, C a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 8 \, B a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - B a^{2}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}}}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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